Math
posted by Ron on .
Suppose f(n+1)/f(n)= n for all positive integers of n. If f (1)=1, find the numerical value of f(6).
How do i figure out this?

f(n+1)/f(n)= n
f(n+1)=n*f(n)
Start with f(1)=1
Then for n=1
f(2)=f(1+1)=1*f(1)=1
f(3)=f(2+1)=2*f(2)=2*1=2
f(4)=f(3+1)=3*f(3)=3*2=6
f(5)=f(4+1)=4*f(4)=4*6=24
f(6)=....
Can you complete this?