Write formulas for the following.

1. potassium hexacyanoferrate(III)
2. sodium hexafluoroaluminate
3. Pentaaquabromomanganese(III) sulfate
4. hexaamminechromium(III) nitrate
5. sodium tetrahydroxochromate(III)
6.trans-dichlorobis(ethylenediamine)cobalt (III) chloride
7.hexaammineruthenium(III) tetrachloronickelate(II)
8.tetraamminecopper(II) pentacyanohydroxoferrate(III)
9. potassium diaquatetrabromovanadate(III)
10.diamminezinc iodide

well the first one is K3[Fe(CN)6] T_T i'm looking for it too T.T

Sure! Here are the formulas for the compounds you listed:

1. potassium hexacyanoferrate(III) - K3[Fe(CN)6]
2. sodium hexafluoroaluminate - Na3AlF6
3. Pentaaquabromomanganese(III) sulfate - [Mn(H2O)5SO4]2
4. hexaamminechromium(III) nitrate - [Cr(NH3)6](NO3)3
5. sodium tetrahydroxochromate(III) - Na3[Cr(OH)4]
6. trans-dichlorobis(ethylenediamine)cobalt (III) chloride - trans-[CoCl2(en)2]Cl
7. hexaammineruthenium(III) tetrachloronickelate(II) - [Ru(NH3)6][NiCl4]
8. tetraamminecopper(II) pentacyanohydroxoferrate(III) - [Cu(NH3)4][Fe(CN)5(OH)]
9. potassium diaquatetrabromovanadate(III) - K[VOBr4(H2O)2]
10. diamminezinc iodide - [Zn(NH3)2]I2

1. The formula for potassium hexacyanoferrate(III) can be determined by understanding the chemical symbols and valence states of each element in the compound.

- Potassium has the symbol K and a valence state of +1.
- Hexacyanoferrate(III) is a complex ion with the formula [Fe(CN)6]3-. The iron (Fe) has a valence state of +3, and each cynaide (CN) ligand has a valence state of -1.

Putting all the information together, the formula for potassium hexacyanoferrate(III) is K3[Fe(CN)6].

2. The formula for sodium hexafluoroaluminate can be determined using a similar approach.

- Sodium has the symbol Na and a valence state of +1.
- Hexafluoroaluminate is a complex ion with the formula [AlF6]3-. The aluminum (Al) has a valence state of +3, and each fluoride (F) ligand has a valence state of -1.

Putting all the information together, the formula for sodium hexafluoroaluminate is Na3[AlF6].

3. The formula for Pentaaquabromomanganese(III) sulfate can be determined in a similar way.

- Pentaaquabromomanganese(III) is a complex ion with the formula [Mn(H2O)5Br]2+. The manganese (Mn) has a valence state of +3, the water (H2O) ligands are neutral, and the bromine (Br) has a valence state of -1.
- Sulfate is a polyatomic ion with the formula SO4^2-.

Putting all the information together, the formula for Pentaaquabromomanganese(III) sulfate is [Mn(H2O)5Br]2(SO4).

4. The formula for hexaamminechromium(III) nitrate can be determined using the same approach.

- Hexaamminechromium(III) is a complex ion with the formula [Cr(NH3)6]3+. The chromium (Cr) has a valence state of +3, and each ammonia (NH3) ligand is neutral.
- Nitrate is a polyatomic ion with the formula NO3-.

Putting all the information together, the formula for hexaamminechromium(III) nitrate is [Cr(NH3)6](NO3)3.

5. The formula for sodium tetrahydroxochromate(III) can be determined similarly.

- Sodium has the symbol Na and a valence state of +1.
- Tetrahydroxochromate(III) is a complex ion with the formula [Cr(OH)4]-. The chromium (Cr) has a valence state of +3, and each hydroxide (OH) ligand has a valence state of -1.

Putting all the information together, the formula for sodium tetrahydroxochromate(III) is Na[Cr(OH)4].

Note: Please give me a moment to calculate the formulas for the remaining compounds.