An object is thrown up at an angle of 40.0 degree above the horizontal and reaches a maximum height H.
If the angle is now doubled to 80.0^degree, but nothing else is changed, its maximum height will be
a. 1.67 H.
b. 2.00 H.
c. 2.35 H.
d. 4.00 H.
The maximum height reached is proportional to (V^2/g) sin^2 theta
V and g do not change.
Calculate the ratio (sin80/sin40)^2
That, times H, will be the answer.