Friday
April 25, 2014

Homework Help: calculus

Posted by nic on Tuesday, January 25, 2011 at 10:30pm.

please help! Find an equation of the tangent line to the curve at the point (-1, 1).
y = 5x3 - 6x.
y=? ...............i keep getting y=x+2 and its wrong. can someone please help?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...
Applied Calculus...... - Find the slope m of the tangent line to the graph of ...
calculus - Consider line segments which are tangent to a point on the right half...
please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...
calculus - ind an equation of the tangent line to the curve at the given point. ...
Calculus - the curve: (x)(y^2)-(x^3)(y)=6 (dy/dx)=(3(x^2)y-(y^2))/(2xy-(x^3)) a...
calculus - Consider the curve given by the equation y^3+3x^2y+13=0 a.find dy/dx...
Calculus - If f(x)=(3x)/(1+x^2) find f′(4). Use this to find the equation ...

Search
Members