specific gravity:
Suppose the hydrometer has a cylindrical stem of cross-sectional area 0.400 cm2. The total volume of the bulb and stem is 8.8 cm3 and the mass of the hydrometer
is 4.8 gm.
(c) What is the lowest specific gravity that can be measured with this hydrometer?
I'm not sure how to start this question, can anyone tell me what to do?
Thanks.
well if the density of the fluid is less than the density of the hydrometer, the hydrometer sinks.
spgr fluid>4.8/8.8
Thanks!
To determine the lowest specific gravity that can be measured with this hydrometer, you need to consider its design and specifications.
Specific gravity is the ratio of the density of a substance to the density of a reference substance. In this case, the reference substance is usually water. The specific gravity of water is 1.
In order to measure the specific gravity of a liquid, a hydrometer is used. A hydrometer works on the principle of buoyancy. When the hydrometer is placed in a liquid, it displaces a certain volume of the liquid based on its weight. The greater the specific gravity of the liquid, the less it is displaced by the hydrometer.
In this problem, we have the dimensions and mass of the hydrometer. To find the lowest specific gravity that can be measured, we need to determine the minimum amount of liquid that will displace enough of the hydrometer to give a measurable reading.
The volume of the stem is given as 8.8 cm³, and the cross-sectional area of the stem is given as 0.400 cm². By dividing the volume by the cross-sectional area, we can find the height of the liquid that would fully submerge the hydrometer stem.
Height of liquid = Volume of stem / Cross-sectional area of stem
Height of liquid = 8.8 cm³ / 0.400 cm²
Height of liquid = 22 cm
Therefore, the lowest specific gravity that can be measured with this hydrometer is the specific gravity of a liquid that would fully submerge the hydrometer stem up to a height of 22 cm.