Let h be the function defined by the equation below.
h(x)= x^3-x^2+x+6
h(-8)
To find h(-8), we substitute -8 into the function h(x) and evaluate it.
h(-8) = (-8)^3 - (-8)^2 + (-8) + 6
Now, we simplify the expression.
= -512 - 64 - 8 + 6
= -578
Therefore, h(-8) equals -578.
To find the value of h(-8) for the given function h(x), substitute -8 in place of x in the equation and simplify.
h(x) = x^3 - x^2 + x + 6
Substituting x = -8:
h(-8) = (-8)^3 - (-8)^2 + (-8) + 6
Simplifying:
h(-8) = -512 - 64 - 8 + 6
h(-8) = -578
Therefore, h(-8) = -578.
This is calculus?
h(x)= x^3-x^2+x+6
h(-8)
Plug -8 in for x and do the math.