Posted by Jill on Tuesday, January 25, 2011 at 11:15am.
number of all possible triples selected = C(19,3) = 969
number with exactly one classical, 2 from the others
= C(5,1)xC(14,2) = 5(91) = 455
prob of your event = 455/969
don't understand your answer Reiny
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