Potency of HCl(l) is 35% (w/w) and density 1.19 g/cm3. Calculate the molarity of the Acid? [Molecular Weight of HCl is 36.5].
mass of 1000 mL is 1.19 g/cc x 1000 cc = ??g,].
How much of that is HCl? ??g x 0.35 = xx g.
How many moles is that? xx g HCl/molar mass HCl.
moles/L is definition of molarity.
To calculate the molarity of the HCl solution, we first need to determine the number of moles of HCl present in the solution.
Step 1: Calculate the mass of HCl present in 100 grams of the solution.
The solution is 35% (w/w), which means it contains 35 grams of HCl in 100 grams of the solution.
So, the mass of HCl in the solution is 35 grams.
Step 2: Calculate the volume of the solution.
Given the density of the solution is 1.19 g/cm3, we need to convert the mass of the solution to volume.
To find the volume, divide the mass by density:
Volume = mass / density = 100 grams / 1.19 g/cm3 = 84.03 cm3.
Step 3: Convert the volume of the solution from cm3 to liters.
Since 1 liter is equal to 1000 cm3, the volume of the solution is 84.03 cm3 / 1000 = 0.08403 liters.
Step 4: Calculate the molarity of the HCl solution.
Molarity (M) = moles of solute / volume of solution (in liters).
To find the number of moles of HCl, divide the mass by the molar mass.
Mass of HCl = 35 grams.
Molar mass of HCl = 36.5 g/mol.
Moles of HCl = Mass of HCl / Molar mass of HCl = 35 grams / 36.5 g/mol = 0.958 mol.
Molarity (M) = 0.958 mol / 0.08403 L = 11.4 M.
Therefore, the molarity of the HCl solution is 11.4 M.