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November 23, 2014

November 23, 2014

Posted by **anonymous** on Tuesday, January 25, 2011 at 12:17am.

- science -
**drwls**, Tuesday, January 25, 2011 at 1:43amThe surface acceleration of gravity is proportional to M/R^2.

On the star surface, g will be higher by a factor 1000/(1/5)^2 = 25000.

So, multiply the weight on Earth by that factor

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