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April 18, 2014

April 18, 2014

Posted by **Jennifer** on Monday, January 24, 2011 at 7:42pm.

- Algebra 2 -
**helper**, Monday, January 24, 2011 at 8:03pmL = no. of liters of 80% solution

.80L = value of 80% solution

10 - L = no. of liters of 40% solution

.40(10 - L) = value of 40% solution

.48(10) = value of mixture

.80L + .40(10 - L) = .48(10)

Solve for L

L = no. of liters of 80% solution

10 - L = no. of liters of 40% solution

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