Posted by Palak on Monday, January 24, 2011 at 7:22pm.
q1 = heat released to cool water from 10 C to zero C.
q1 = mass water x specific heat water x (Tfinal-Tinitial).
q2 = heat released to freeze liquid water at zero C to solid ice at zero C.
qw2 = mass water x heat fusion.
Total q = q1 + q2
Related Questions
Chemistry - calculate the energy in joules lost when 70.0 grams of water cools ...
Chemistry - how many joules of heat are given off when 5.0 grams of water cool ...
chemistry - Calculate the enthalpy change for converting 10.0g of ice at -25 ...
Chemistry II - Calculate the energy pulled from 500 grams of Water at 20.0 ...
chemistry - A 10.0 grams piece of gold 90.0 Celsius was stirred into 15.0ml of ...
chemistry - the specific heat capacity of mercury is 0.033 cal/(g))degrees ...
Chemistry - Calculate the change in heat when 3.05g of water vapor (steam) at ...
Chemistry - "Energy is released when 100 kg of steam at 150 degrees Celsius...
Chemistry - A 100g sample of water at 90 degrees celsius is added to a 100g ...
Chemistry Help - The specific heat of zinc is 0.386 J/g degrees Celsius. How ...
For Further Reading