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February 1, 2015

February 1, 2015

Posted by **jackie** on Monday, January 24, 2011 at 4:11pm.

a ball has dropped from a height of 15m and bounces 60% of the previous height. the total distance ball travels after the 9th bounce is...

i got this equation done but i do not know how to calculate this to find the answer

15(0.6^9-1)/0.6-1

could you show me how to do it?

- math -
**Reiny**, Monday, January 24, 2011 at 4:41pmthe trick here is that the first bounce has a different pattern than the following bounces

distance of 1st bounce = 15 ,...... just down

distance of 2nd bounce = 2(15)(.6) , ..... up and down

distance of 3rd bounce = 2(15)(.6^2)

distance of 4th bounce = 2(15(.6^3)

...

distance of 9th bounce = 2(15)(.6^8)

so total distance

= 15 + 8 terms

= 15 + 2(15)(.6) [ (.6^8 - 1)/(.6 - 1)]

I get 59.24

check my arithmetic

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