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pls help me solve this problem..

charges of +2.0, 3.0 and -8.0µC are placed at the vertices of an equilateral triangle of a side 10 cm. Calculate the magnitude of the force acting on the -8µC charge due to the other two charges.

  • physics -

    Add the vector sum of
    -k*2*8*10^-12/0.1^2 and
    applied 60 degrees apart.

    k is the Coulomb constant,
    8.99*10^9 N/m^2*C^2

    There will be an attraction force in a direction between the two other points of the triangle. It will not bisect the angle, because the forces are unequal.

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