Posted by **lisa** on Sunday, January 23, 2011 at 11:23pm.

A dehydrated patient needs a 7.9% saline IV. Unfortunately, the hospital only has bags of 3% and 10% saline solutions. How many liters of each of these solutions should be mixed together to yield 3 liters of the desired concentration?

- algebra -
**helper**, Sunday, January 23, 2011 at 11:33pm
I answered your post below with this same question. Please check to see if your post was answered before re-posting.

I pasted the answer here for you.

x = liters of 3% solution

3 - x = liters of 10% solution

.03x = value 3% solution

.10(3 - x) = value 10% solution

3 = liters of 7.9% mixture

.079(3) = 0.237 = value 7.9% mixture

.03x + .10(3 - x) = 0.237

Solve for x, which is number of liters of 3% solution.

(3 - x) = number of liters of 10% solution

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