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September 14, 2014

September 14, 2014

Posted by **Chloe** on Sunday, January 23, 2011 at 11:20pm.

log2(log4x)=1 and

solve for x and y:

(1/2)^x+y= 16 logx-y8=-3

- Math -
**helper**, Sunday, January 23, 2011 at 11:41pmlog2(log4x)=1

Rewrite as

(log((log(x))/(log(4))))/(log(2)) = 1

Divide both sides by 1/(log(2)):

log((log(x))/(log(4))) = log(2)

Cancel logarithms by taking exp of both sides:

(log(x))/(log(4)) = 2

Divide both sides by 1/(log(4)):

log(x) = 2 log(4)

Cancel logarithms by taking exp of both sides:

x = 16

You need to rewrite the 2nd with parentheses.

As written it is not clear.

(1/2)^x+y= 16 logx-y8=-3

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