Posted by Chloe on Sunday, January 23, 2011 at 11:20pm.
I am having trouble figuring out how to solve these logarithms. Could someone please help!
log2(log4x)=1 and
solve for x and y:
(1/2)^x+y= 16 logxy8=3

Math  helper, Sunday, January 23, 2011 at 11:41pm
log2(log4x)=1
Rewrite as
(log((log(x))/(log(4))))/(log(2)) = 1
Divide both sides by 1/(log(2)):
log((log(x))/(log(4))) = log(2)
Cancel logarithms by taking exp of both sides:
(log(x))/(log(4)) = 2
Divide both sides by 1/(log(4)):
log(x) = 2 log(4)
Cancel logarithms by taking exp of both sides:
x = 16
You need to rewrite the 2nd with parentheses.
As written it is not clear.
(1/2)^x+y= 16 logxy8=3