Saturday
March 25, 2017

Post a New Question

Posted by on .

I am having trouble figuring out how to solve these logarithms. Could someone please help!

log2(log4x)=1 and

solve for x and y:
(1/2)^x+y= 16 logx-y8=-3

  • Math - ,

    Answered in a later post.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question