Post a New Question
posted by Chloe on Sunday, January 23, 2011 at 10:58pm.
I am having trouble figuring out how to solve these logarithms. Could someone please help! log2(log4x)=1 and solve for x and y: (1/2)^x+y= 16 logx-y8=-3
Answered in a later post.
More Related Questions