Physics
posted by David on .
An airplane must reach a speed of 185 mi/h to take off. If the runway is 467 m long, what is the minimum value of the acceleration that will allow the airplane to take off successfully? m/s2
I have been trying the formula vf^2=Vi^2+2AD and solving for A
SO my work has been
185^2=0^2+2A(467)
34225/934=A
36.643=A
I'm assuming my mistake is using speed as Vf but not sure how else to do it. TIA

Be careful of units.
You expressed the runway length in m (meters), but the takeoff speed is expressed in mi/h (miles/hour). You will need to do some units conversion.