Posted by Anon on Sunday, January 23, 2011 at 10:47pm.
A decrease in sound level by 61 dB amounts to a factor of 10^6.1 = 1.26^10^6 in sound power per area. To achieve this, you need to be sqrt(1.25*10^6) = 1122 times farther away. That corresonds to 30*1122 = 33,660 m away. (about 21 miles)
thank you :)
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