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April 2, 2015

April 2, 2015

Posted by **Anonymous** on Sunday, January 23, 2011 at 10:06pm.

- calculus -
**Reiny**, Sunday, January 23, 2011 at 10:14pmlet each side of base be x

let the height be y

x^2y = 50

y = 50/x^2

cost = 44x^2 + 4(10)(xy) + 26x^2 , where cost is in cents

=70x^2 = 40x(50/x^2)

= 70x^2 + 2000/x

- calculus -
**Anonymous**, Sunday, January 23, 2011 at 11:23pmwhich one is the answer?

- calculus -
**Damon**, Monday, January 24, 2011 at 5:32amThe question asked for the cost.

- calculus -
**Danny**, Wednesday, January 23, 2013 at 7:13pmDamon the answer is wrong.

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