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Posted by **curious student** on Sunday, January 23, 2011 at 10:04pm.

3/32+3/16+3/8+...+12288

so far ive gotten that a=3/32 and r=2/1

can you please help me further

- math -
**Reiny**, Sunday, January 23, 2011 at 10:20pmsum = [sigma] 3/2^(6-i), i from 1 to 18

- math -
**curious student**, Sunday, January 23, 2011 at 10:36pmwhat does "i" stand for?

- math -
**Reiny**, Sunday, January 23, 2011 at 10:53pmIn sigma notation we traditionally use i or n as the index of the notation.

You had asked for the expression in "sigma notation"

What you started doing is attempting to add up the values using a geometric series.

What you started is correct, but that was not asked for.

If you want the actual sum, you will first have to find how many terms there are, that is, what term number is 12288

the use the formula

S_{n}= a(r^n - 1)/(r-1)

- math -
**curious student**, Sunday, January 23, 2011 at 10:56pmthank you muchly!

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