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Algebra
Simplifying expressions
Polynomials
simplify as much as possible
y^2�ã48yv^2 - v�ã12 y^5
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25²+20x+4=0
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Simplify:
(a) 4�ã7 (2�ã3 +3�ã6 -�ã7 ) (b) (3�ã7 -�ã2 )squared (c) (16�ã24)/(4�ã96) (d) 7/(�ã20 ) - 4/(�ã12)
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I will assume your ã is supposed to be a √ To do these, you should know the basic laws for
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Find an example of 2 by2 matrices with a12 = .5 for which:
a. A^2 = I b. A^-1 = A^T c. A^2 = A By the way, a12 means the first
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I will do the first one: let A = a .5 b c the A^2 = (a^2+b/2) (a/2+c/2) (ab + bc) (b/2+c^2) then
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Find a12 in a geometric series for which a12 = 32 and r= -4
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Hmmm. I'd say a12=32. Maybe fix your typo and use the usual formula an = ar^(n-1) also, I think you
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multiply and simplify
�ã12 �ã24
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What is ã ?
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Simplify
�ã12+�ã18-�ã27+�ã50 thnx a lot any help is greatly appriceted....
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that is sqrt12 + sqrt18 - sqrt27 + sqrt 50
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Which of the following is a balanced equation?
a. A1 + CuSO4= Cu + A12 (SO4)3 b. 2 A1 + CuSO4 = Cu + A12 (SO4)3 c. A1 + 3 CuSO4 =
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d/ 2 A1 + 3 CuSO4 = 3 Cu + A12 (SO4)3
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Let A1,A2...A12 be twelve equally spaced points on a circle with radius 1. Find
(A1 A2)^2 + (A1 A3)^2 + ... + A11 A12)^2. (The
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What does the sums of squares of lengths make you think about? If you still don't know, what neat
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�ã27 + �ã12 - �ã32 - �ã8
�ã27 = �ã3*3*3 = 3�ã3 �ã12 = �ã2*2*3 = 2�ã3 �ã32 = �ã2*2*2*2*2 = 4�ã2 �ã8 =
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Ok sorry I just cant make that radical sign for some reason but that ã is supposed to be a radical
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help!-matrix size is 3x3
clues for the encoding matrix: 1. all entries are one digit and positive 2. a11, a12, a13 are all equal
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2. 1, 1, 1 sum = 3, no other sum is prime 3. 3 4. only prime between 3 and 7 is 5 so a22 is 5 so a33
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1/2�ã12 times 8�ã3
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assuming that you mean 1/2 √12 * 8√3 we have √4√3/2 * 8√3 2√3/2 * 8√3 8*3 24
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