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physics

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1 kg of ice at 0° C is mixed with 9 kg of water at 50° C (The latent heat of ice is 3.34x105 J/kg and the specific heat capacity of water is 4160 J/kg). What is the resulting temperature?

  • physics - ,

    Heat into ice = 1*3.34*10^5 +(T-0)(4160)
    Heat out of water = 4160 (50-T)(9)

    set equal and solve for T

  • physics - ,

    omg thank you so much!!

  • physics - ,

    but ? where did the 1.3 come frm

  • physics - ,

    1*3 is one times 3
    1 kilogram times latent heat of ice

  • physics - ,

    budhu hai kya tu

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