i need to find the perimeter of a triangle with the demensions : 2(q^2-3q) , q+10 , and q^2 .
add them:
2q^2-6q+q+10+q^2=3q^2-5q+10
check that.
2 q^2 -6 q + q + 10 + q^2
3 q^2 -5 q + 10
To find the perimeter of a triangle, you need to add the lengths of all three sides.
In this case, we have the dimensions of the triangle as 2(q^2 - 3q), q + 10, and q^2.
Step 1: Write down the formula for the perimeter of a triangle.
Perimeter = Side 1 + Side 2 + Side 3
Step 2: Substitute the given dimensions into the formula.
Perimeter = 2(q^2 - 3q) + (q + 10) + q^2
Step 3: Simplify the equation.
Expand the terms within parentheses and combine like terms.
Perimeter = 2q^2 - 6q + q + 10 + q^2
= 3q^2 - 4q + 10
So, the perimeter of the triangle with dimensions 2(q^2 - 3q), q + 10, and q^2 is 3q^2 - 4q + 10.