Posted by **Anonymous** on Sunday, January 23, 2011 at 3:13pm.

A baseball is hit off a 1 meter high tee at an angle of 25 degrees and at a speed of 43 m/s. How far to the nearest tenth of a meter does it travel horizontally?

- Physics -
**Damon**, Sunday, January 23, 2011 at 3:29pm
vertical problem

Vi = 43 sin 25 = 18.17

v = Vi - 9.8 t

0 = 18.17 - 9.8 t at top

t to top = 1.85 seconds to top

h = 1 + 18.17 (1.85) - 4.9 (1.85)^2

h = 1 + 33.61 - 16.77 = 17.8 m at top at 1.85 s

now fall from 17.8 m

17.8 = 4.9 t^2

t = 1.91 s to fall

total time in air = 1.85+1.91 = 3.76 s in the air

how far, horizontal problem

u = constant horizontal speed = 43 cos 25 = 39 m/s

distance = 39 * 3.76 = 147 meters

a football field and more than a half

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