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Physics

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A baseball is hit off a 1 meter high tee at an angle of 25 degrees and at a speed of 43 m/s. How far to the nearest tenth of a meter does it travel horizontally?

  • Physics - ,

    vertical problem
    Vi = 43 sin 25 = 18.17
    v = Vi - 9.8 t
    0 = 18.17 - 9.8 t at top
    t to top = 1.85 seconds to top
    h = 1 + 18.17 (1.85) - 4.9 (1.85)^2
    h = 1 + 33.61 - 16.77 = 17.8 m at top at 1.85 s
    now fall from 17.8 m
    17.8 = 4.9 t^2
    t = 1.91 s to fall
    total time in air = 1.85+1.91 = 3.76 s in the air
    how far, horizontal problem
    u = constant horizontal speed = 43 cos 25 = 39 m/s
    distance = 39 * 3.76 = 147 meters
    a football field and more than a half

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