i know the formula of a rectangles surface area is SA= 2(lw)+(wh)+(lh), but when the dimensions are : 2a for the height, a for the width, and 3a for the length, how do i solve?

To solve for the surface area of a rectangle with dimensions 2a for the height, a for the width, and 3a for the length, you can use the formula SA = 2lw + wh + lh.

1. Substitute the given values into the formula:
- Length (l) = 3a
- Width (w) = a
- Height (h) = 2a

2. Plug in the values:
SA = 2(3a)(a) + (a)(2a) + (3a)(2a)

3. Simplify each term:
SA = 6a^2 + 2a^2 + 6a^2

4. Combine like terms:
SA = 6a^2 + 2a^2 + 6a^2 = 14a^2

Therefore, the surface area (SA) of a rectangle with dimensions 2a for the height, a for the width, and 3a for the length is 14a^2.

Put l=3a, w=a, h=2a

into your formula to get
S = 2(lw+wh+lh)
= 2(3a*a + a*2a + 3a*2a)
= 2(11a²)
= 22a²

Check my work.

Bote: The parentheses in your formula have been misplaced. The correct form is:
S=2(lw+wh+lh)

I have no clue I suck at math can someone PLEASE help me to!??!

girl bye

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