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Posted by on Sunday, January 23, 2011 at 1:38pm.

What is the pH of a one liter auqueous solution to which has been added 0.2 moles of acetic acid (CH3COOH)?

  • Chemistry - , Sunday, January 23, 2011 at 1:54pm

    CH3COOH + H2O = CH3COO- + H3O+
    Acid acetic is a weak acid so not all of it will dissociate. The constant for acid acetic is 1.8 . 10^-5
    therefore 1.8x10^-5=(x^2)/(0.2-x)
    x is the amount that disociated
    solve the equation and x is 1.88x10^-3
    pH=-log(pH)=-log(1.88x10^-3)=2.72

  • Chemistry - , Sunday, January 23, 2011 at 2:03pm

    thank you so very much this helped so much!!!!!

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