Chemistry
posted by Chris on .
What is the pH of a one liter auqueous solution to which has been added 0.2 moles of acetic acid (CH3COOH)?

CH3COOH + H2O = CH3COO + H3O+
Acid acetic is a weak acid so not all of it will dissociate. The constant for acid acetic is 1.8 . 10^5
therefore 1.8x10^5=(x^2)/(0.2x)
x is the amount that disociated
solve the equation and x is 1.88x10^3
pH=log(pH)=log(1.88x10^3)=2.72 
thank you so very much this helped so much!!!!!