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January 26, 2015

January 26, 2015

Posted by **holly** on Sunday, January 23, 2011 at 12:53pm.

- math -
**Henry**, Sunday, January 23, 2011 at 9:10pmQ4. cosA = 2/3 = X/r,

X^2 + Y^2 = r^2,

2^2 + Y^2 = 3^2,

4 + Y^2 = 9,

Y^2 = 9 - 4 = 5,

Y = +-sqrt5,

Y = -sqrt5(Q4).

1/cotA = tanA = Y/X = -(sqrt5/2).

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