physics
posted by Anonymous on .
Calculate the maximum height using the initial speed, halftime, and angle. The initial speeed is 18m/s, half time is 1.8, and the angle is 75. And how is this written out to solve.

Max height H is given by
2gH = (Vo sin A)^2
You don't need the halftime, T, if you know g.
Vo sin A = g T
g = Vo sinA /T
2 Vo sin A*H/T = (Vo sin A)^2
H = Vo sinA*T/2
in other words, the average vertical velocity component multiplied by the halftime.