Posted by **Anonymous** on Sunday, January 23, 2011 at 11:51am.

Calculate the maximum height using the initial speed, half-time, and angle. The initial speeed is 18m/s, half time is 1.8, and the angle is 75. And how is this written out to solve.

- physics -
**drwls**, Sunday, January 23, 2011 at 12:06pm
Max height H is given by

2gH = (Vo sin A)^2

You don't need the half-time, T, if you know g.

Vo sin A = g T

g = Vo sinA /T

2 Vo sin A*H/T = (Vo sin A)^2

H = Vo sinA*T/2

in other words, the average vertical velocity component multiplied by the half-time.

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