Two bullets have masses of 4.6 g and 11 g,
respectively. Each is fired with a speed of 41.0
m/s.
a) What is the kinetic energy of the first
bullet?
Answer in units of J.
a) Kinetic Energy = (1/2)*M1*V^2
M1 = 0.0046 kg
Information about the second bullet is not needed to answer this question.
KE= 0.0046 x 41 x 41 x 0.5
= 3.8663 Joules
To find the kinetic energy of the first bullet, we can use the formula for kinetic energy:
Kinetic Energy (KE) = (1/2) * mass * velocity^2
Given:
Mass of the first bullet (m1) = 4.6 g = 0.0046 kg (converting grams to kilograms)
Velocity of the first bullet (v1) = 41.0 m/s
Plugging in these values into the formula, we get:
KE1 = (1/2) * 0.0046 kg * (41.0 m/s)^2
Now, let's calculate the kinetic energy of the first bullet.