It's similar to the previous question.
Start with drawing a diagram if the book did not supply one.
O is the vertex of the pyramid.
Let D be the centre of the rectangle PQRS, and A=centre of side PQ.
OAD is a right triangle where OD is the height=h, and OA is the height of the slant face OPQ.
By Pythagoras theorem, we find
Area of one slant face
Area of 4 slant faces
Area of rectangular base
Equate the sum of areas to total surface area
Solve for h. I get 7.2 approx.
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