Posted by Erica on .
Given function f defined by f(x) = ( 1- x)³. What are all values of c, in the closed interval [0,3], that satisfy the conditions of the Mean Value Theorem?
Mean-value theorem -
The mean value theorem states that a continuous function between x=a and x=b will have at least one tangent parallel to the chord AB.
For f(x)=(1-x)³, the chord between 0 and 3 has a slope of
The value(s) of c required must satisfy
So, differentiate with respect to x:
and solve for
x=0 and x=2
Reject any solution that is not on the interval [0,3].
mean value theorem of x^3+x-6 with range of [0,2]