Thursday

October 23, 2014

October 23, 2014

Posted by **Sangita** on Saturday, January 22, 2011 at 8:27pm.

the action of two forces. One is a forward

force of 1153 N provided by traction between

the wheels and the road. The other is a 939 N resistive force due to various frictional forces.

How far must the car travel for its speed to

reach 2.0 m/s?

Answer in units of m.

- Physics -
**drwls**, Saturday, January 22, 2011 at 10:51pmOne step at a time.

First compute the net force acting:

F = 1153 - 939 = 214 N

Then compute the acceleration rate a using

F = m a; a = F/m

Then compute the time t required to reach velocity V:

t = V/a

The distance travelled is

X = (1/2) a t^2

**Answer this Question**

**Related Questions**

physics - a 2500 kg car accelerates from rest under the act of two forces. 1.) a...

AP physics - A 1280-kg car starts from rest and accelerates to 80 km/h in 23.0 s...

physics - A boat moves through the water with two forces acting on it. One is a ...

physics 11 - A 1200 kg car on a horizontal surface starts from rest and ...

Physics - A 1900 car starts from rest and drives around a flat 50--diameter ...

physics - A boat moves through the water with two forces acting on it. One is a ...

Physics - A boat moves through the water with two forces acting on it. One is a ...

physics - A 2.9 × 103 kg car accelerates from rest at the top of a driveway that...

Physics - A 4.0 × 103 kg car accelerates from rest at the top of a driveway that...

physics - A 3.1 × 103 kg car accelerates from rest at the top of a driveway that...