posted by Sangita on .
A 2.0×103 kg car accelerates from rest under
the action of two forces. One is a forward
force of 1153 N provided by traction between
the wheels and the road. The other is a 939 N resistive force due to various frictional forces.
How far must the car travel for its speed to
reach 2.0 m/s?
Answer in units of m.
One step at a time.
First compute the net force acting:
F = 1153 - 939 = 214 N
Then compute the acceleration rate a using
F = m a; a = F/m
Then compute the time t required to reach velocity V:
t = V/a
The distance travelled is
X = (1/2) a t^2