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A 2.0×103 kg car accelerates from rest under
the action of two forces. One is a forward
force of 1153 N provided by traction between
the wheels and the road. The other is a 939 N resistive force due to various frictional forces.
How far must the car travel for its speed to
reach 2.0 m/s?
Answer in units of m.

  • Physics -

    One step at a time.

    First compute the net force acting:
    F = 1153 - 939 = 214 N

    Then compute the acceleration rate a using
    F = m a; a = F/m

    Then compute the time t required to reach velocity V:
    t = V/a

    The distance travelled is
    X = (1/2) a t^2

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