# College Algebra

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Divide.
(9x^3-10+19+6x^4)/(-2x^2+3x-3)

where Q(x) is the quotient and R(x) is the remainder.

• College Algebra -

First rearrange and simplify the numerator to:
6x^4 + 9x^3 + 9

Just divide as your would with any long division problem.

If you post your answer I can tell you if you are correct.

Is there something in particular you do not understand?

• College Algebra -

Just not good at division

• College Algebra -

I'll try, but the formatting here doesn't allow for easy alignment of columns.

xxxxxxxxxxxxx-3x^2 - 9x - 9
-2x^2+3x-3 |6x^4 + 9x^3 + 0x^2 + 0x +9
------------6x^4 - 9x^3 + 9x^2
subtraction-------18x^3 - 9x^2
------------------18x^3 - 27x^2 + 27x
subtraction-------------18x^2 - 27x + 9
------------------------18x^2-27x + 27
subtractionxxxxxxxxxxxxxxxxxxxxxxx -18

Q(x)+ R(x)/ -2x^2+3x-3,
-3x^2 - 9x - 9 + -18/(-2x^2 + 3x - 3)

I don't know how you will follow this because of the formatting.

• College Algebra -

Ok I will try to figure it out and ask if I need anymore questions. thanks for your help

• College Algebra -

You're welcome and good luck :).