College Algebra
posted by jen .
Please help me
Divide.
(9x^310+19+6x^4)/(2x^2+3x3)
Write your answer in the form Q(x)+ R(x)/ 2x^2+3x3,
where Q(x) is the quotient and R(x) is the remainder.

First rearrange and simplify the numerator to:
6x^4 + 9x^3 + 9
Just divide as your would with any long division problem.
If you post your answer I can tell you if you are correct.
Is there something in particular you do not understand? 
Just not good at division

I'll try, but the formatting here doesn't allow for easy alignment of columns.
xxxxxxxxxxxxx3x^2  9x  9
2x^2+3x3 6x^4 + 9x^3 + 0x^2 + 0x +9
6x^4  9x^3 + 9x^2
subtraction18x^3  9x^2
18x^3  27x^2 + 27x
subtraction18x^2  27x + 9
18x^227x + 27
subtractionxxxxxxxxxxxxxxxxxxxxxxx 18
Answer in the form
Q(x)+ R(x)/ 2x^2+3x3,
3x^2  9x  9 + 18/(2x^2 + 3x  3)
I don't know how you will follow this because of the formatting. 
Ok I will try to figure it out and ask if I need anymore questions. thanks for your help

You're welcome and good luck :).