Posted by jen on Saturday, January 22, 2011 at 7:42pm.
Please help me
Divide.
(9x^310+19+6x^4)/(2x^2+3x3)
Write your answer in the form Q(x)+ R(x)/ 2x^2+3x3,
where Q(x) is the quotient and R(x) is the remainder.

College Algebra  helper, Saturday, January 22, 2011 at 7:55pm
First rearrange and simplify the numerator to:
6x^4 + 9x^3 + 9
Just divide as your would with any long division problem.
If you post your answer I can tell you if you are correct.
Is there something in particular you do not understand?

College Algebra  anon, Saturday, January 22, 2011 at 8:05pm
Just not good at division

College Algebra  helper, Saturday, January 22, 2011 at 8:22pm
I'll try, but the formatting here doesn't allow for easy alignment of columns.
xxxxxxxxxxxxx3x^2  9x  9
2x^2+3x3 6x^4 + 9x^3 + 0x^2 + 0x +9
6x^4  9x^3 + 9x^2
subtraction18x^3  9x^2
18x^3  27x^2 + 27x
subtraction18x^2  27x + 9
18x^227x + 27
subtractionxxxxxxxxxxxxxxxxxxxxxxx 18
Answer in the form
Q(x)+ R(x)/ 2x^2+3x3,
3x^2  9x  9 + 18/(2x^2 + 3x  3)
I don't know how you will follow this because of the formatting.

College Algebra  jen, Saturday, January 22, 2011 at 8:27pm
Ok I will try to figure it out and ask if I need anymore questions. thanks for your help

College Algebra  helper, Saturday, January 22, 2011 at 10:43pm
You're welcome and good luck :).
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