Saturday

January 31, 2015

January 31, 2015

Posted by **jen** on Saturday, January 22, 2011 at 7:42pm.

Divide.

(9x^3-10+19+6x^4)/(-2x^2+3x-3)

Write your answer in the form Q(x)+ R(x)/ -2x^2+3x-3,

where Q(x) is the quotient and R(x) is the remainder.

- College Algebra -
**helper**, Saturday, January 22, 2011 at 7:55pmFirst rearrange and simplify the numerator to:

6x^4 + 9x^3 + 9

Just divide as your would with any long division problem.

If you post your answer I can tell you if you are correct.

Is there something in particular you do not understand?

- College Algebra -
**anon**, Saturday, January 22, 2011 at 8:05pmJust not good at division

- College Algebra -
**helper**, Saturday, January 22, 2011 at 8:22pmI'll try, but the formatting here doesn't allow for easy alignment of columns.

xxxxxxxxxxxxx-3x^2 - 9x - 9

-2x^2+3x-3 |6x^4 + 9x^3 + 0x^2 + 0x +9

------------6x^4 - 9x^3 + 9x^2

subtraction-------18x^3 - 9x^2

------------------18x^3 - 27x^2 + 27x

subtraction-------------18x^2 - 27x + 9

------------------------18x^2-27x + 27

subtractionxxxxxxxxxxxxxxxxxxxxxxx -18

Answer in the form

Q(x)+ R(x)/ -2x^2+3x-3,

-3x^2 - 9x - 9 + -18/(-2x^2 + 3x - 3)

I don't know how you will follow this because of the formatting.

- College Algebra -
**jen**, Saturday, January 22, 2011 at 8:27pmOk I will try to figure it out and ask if I need anymore questions. thanks for your help

- College Algebra -
**helper**, Saturday, January 22, 2011 at 10:43pmYou're welcome and good luck :).

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