Posted by **Alison** on Saturday, January 22, 2011 at 7:15pm.

Given Equation AX + BY + C = 0, which following conditions would be true for graph of line to have a negative slope and a postive y-intercept?

A. A>0, B>0, C>0

B. A>0, B<0, C>0

C. A>0, B>0, C<0

D. A>0, B<0, C<0

I cant figure this out!

- MATH EMERGENCY -
**helper**, Saturday, January 22, 2011 at 7:28pm
In this form

Ax + By + C = 0

Slope m = -A/B

y-intercept b = -C/B

You are looking for, a negative slope

Slope m = -A/B

And, a positive y-intercept

C/B

So,

Ax + By - C = 0

Can you answer now?

- MATH EMERGENCY -
**Alison**, Saturday, January 22, 2011 at 8:02pm
I still don't get it:\

Is C the y-intercept? or B?

How do I know which one is greater or less? This is mind twisting, i don't get it

- MATH EMERGENCY -
**bobpursley**, Saturday, January 22, 2011 at 8:05pm
I would change it to slope intercept form

y=mx+b

y-a/b x -c/b

so for a negative coefficent of x, both a,b have to be positive, or both have to be negative. A positive y intercept means that c or b has to be negative, but not both.

- MATH EMERGENCY -
**Alison**, Saturday, January 22, 2011 at 8:08pm
Ok. That kind of makes sense.

- MATH EMERGENCY -
**Henry**, Sunday, January 23, 2011 at 3:02pm
To have a negative slope and positive

y-int, A and B must have the same sign

, C must have the opposite sign.

Therefore, the answer is C.

If the Eq was in this form:

AX + BY = C; A, B, and C must have the

same sign.

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