Posted by **I HATE MATH!!!** on Saturday, January 22, 2011 at 6:02pm.

can somebody help me with this problem....DONT GIVE ME THE ANSWER JUST HOW TO WORK IT...

2r + 8 / 4 = 3r - 6 /3

- COLLEGE ALGEBRA -
**I HATE MATH!!!**, Saturday, January 22, 2011 at 6:06pm
i think i figured it out.....i think the answer is r=8

- COLLEGE ALGEBRA -
**helper**, Saturday, January 22, 2011 at 6:10pm
Not correct

Post your work and someone can explain what you are doing wrong.

First simplify 8/4 and 6/3

and then combine like terms.

- COLLEGE ALGEBRA -
**I HATE MATH!!!**, Saturday, January 22, 2011 at 6:20pm
helper, its not 8/4 and 6/3. its 2r+8 over 4 = 3r-6 over 3

- COLLEGE ALGEBRA -
**Damon**, Saturday, January 22, 2011 at 6:24pm
That is written

(2r+8)/4 = (3r-6)/3

(r+4)/2 = (r-2)

r+4 = 2(r-2)

r+4 = 2r - 4

8 = r

check

(16+8)/4 =? (24-6)/3

24/4 = ? 18/3

6 = 6 yes, it checks

- COLLEGE ALGEBRA -
**I HATE MATH!!!**, Saturday, January 22, 2011 at 6:25pm
Thanks so much!

- COLLEGE ALGEBRA -
**helper**, Saturday, January 22, 2011 at 6:37pm
(2r + 8)/4 = (3r - 6)/3

Yes, you are correct, r = 8.

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