Posted by I HATE MATH!!! on Saturday, January 22, 2011 at 6:02pm.
can somebody help me with this problem....DONT GIVE ME THE ANSWER JUST HOW TO WORK IT...
2r + 8 / 4 = 3r - 6 /3
COLLEGE ALGEBRA - I HATE MATH!!!, Saturday, January 22, 2011 at 6:06pm
i think i figured it out.....i think the answer is r=8
COLLEGE ALGEBRA - helper, Saturday, January 22, 2011 at 6:10pm
Post your work and someone can explain what you are doing wrong.
First simplify 8/4 and 6/3
and then combine like terms.
COLLEGE ALGEBRA - I HATE MATH!!!, Saturday, January 22, 2011 at 6:20pm
helper, its not 8/4 and 6/3. its 2r+8 over 4 = 3r-6 over 3
COLLEGE ALGEBRA - Damon, Saturday, January 22, 2011 at 6:24pm
That is written
(2r+8)/4 = (3r-6)/3
(r+4)/2 = (r-2)
r+4 = 2(r-2)
r+4 = 2r - 4
8 = r
(16+8)/4 =? (24-6)/3
24/4 = ? 18/3
6 = 6 yes, it checks
COLLEGE ALGEBRA - I HATE MATH!!!, Saturday, January 22, 2011 at 6:25pm
Thanks so much!
COLLEGE ALGEBRA - helper, Saturday, January 22, 2011 at 6:37pm
(2r + 8)/4 = (3r - 6)/3
Yes, you are correct, r = 8.
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