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March 6, 2015

March 6, 2015

Posted by **John** on Saturday, January 22, 2011 at 10:44am.

You can calculate it using the Algebraic equation: gr = R2/r2 x g

R = the radius of the planet

r = the distance from the center of mass of the planet to the center of mass of the object in orbit

g = the gravitational attraction of the planet on objects on its surface

gr = the gravitational attraction of the planet as felt on the less massive object

- Physics -
**drwls**, Saturday, January 22, 2011 at 11:33amYour definition of gr is incorrect. The mass of the object stays the same but the value of the acceleration decreases with altitude.

All you have to do is apply the formula

gr = (R^2/r^2) * g

The value of r 220 miles above the earth's surface is

r = 220 + R, where

R = 3959 miles

All you have to do is calculate the factor

(R/r)^2 = (3959/4179)^2

They want you to express the answer as a percent reduction from 1.000

You cannot actually calculate a force since you were not given a mass value.

- Physics -
**bumble**, Monday, January 24, 2011 at 5:18pmlooks like someone is cheating on their NASA HAS lesson 3 assignment

- Physics -
**BobSheldon**, Monday, January 24, 2011 at 10:04pmhey Bumble, no idea what youre talking about, but if he is cheating on an assignment, why are you on this site looking at his answer? by default, your accusation implies that you also cheated on your homework. FAIL!

- Physics -
**BobSheldon**, Monday, January 24, 2011 at 10:10pmAnd the answer is still wrong, you have the wrong formula and forgot 9.81 as surface grav.

Gr=R^2/R^2 * G

Gr= (6378^2/6598^2) *9.81

Gr= 9 . 166 708 367

IDK about the percent thing

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