Posted by **Hector** on Friday, January 21, 2011 at 5:16pm.

Help!!!

A rectangle piece of cardboard twice as long as wide is to be made into an open box by cutting 2 in. squares from each corner and bending up the sides. (a) Express the volume V of the box as a function of the width W of the piece of cardboard (b) find the domain of the function.

Thanks!

- calculus -
**MathMate**, Friday, January 21, 2011 at 9:40pm
Length = 2W (inches)

Width = W (inches)

Height = 2 inches

V(W)=Length*Width*Height

=2W*W*2

=4W²

The minimum width of the box is 4 inches, which results in a box of zero volume.

Thus the domain of V(W) is [4,∞].

- calculus -
**Hector**, Sunday, January 23, 2011 at 10:50pm
Thanks MathMate!

- factors -
**racky**, Thursday, September 29, 2011 at 9:41pm
well i would find a factor of something by dividing numbers from 1 to 10 and figure it out by dividing it up

## Answer this Question

## Related Questions

- calculus - an open rectangular box is to be made from a piece of cardboard 8 ...
- calculus - By cutting away identical squares from each corner of a rectangular ...
- math - a piece of cardboard is twice as it is wide. It is to be made into a box ...
- calculus optimization problem - by cutting away identical squares from each ...
- maths - an open box of rectangular base is to be made from 24 cm by 45cm ...
- calc - an open box is to be made from a 4 ft by 5 ft piece of cardboard by ...
- Calculus - By cutting away identical squares from each corner of a rectangular ...
- Calculus 1 - A box with an open top is to be constructed from a rectangular ...
- math - A rectangular piece of cardboard 9" x 12" is made into an open box by ...
- Calculus - A box with an open top is to be made from a square piece of cardboard...

More Related Questions