Posted by **John** on Friday, January 21, 2011 at 3:40pm.

A point moving on a straight horizontal

line with an initial velocity of 60 fps to the right

is given an acceleration of 12 fps2 to the left for

8 sec.

Determine (a) the total distance traveled during

the 8-sec interval; (b) the displacement during

the 8-sec interval.

- physics -
**drwls**, Friday, January 21, 2011 at 4:47pm
At the beginning of the 8 s interval, the velocity is 60 ft/s.

At the end of the 8s interval, the velocity is 60 - 12*8 = -36 ft/s

The average velocity during the interval is (60-36)/2 = 12 ft/s

You can multiply that by 8 s for the total displacement.

(a) X = 60 t - 6 t^2

Maximum X value occurs @ dX/dt = 0, where t = 5 s. The value of X at that time is 300 - 150 = 150 ft. Then it goes backwards until t = 8, when

X(final) = 480 - 384 = 96 ft.

Total distance traveled, regardless of direction, is 150 + 96 = 246 ft

(b) Displacement from starting position = 96 feet. We already found that out part (a)

## Answer this Question

## Related Questions

- physics - Points A and B move along two adjacent parallel paths. Initially A is ...
- physics - Points A and B move along two adjacent parallel paths. Initially A is ...
- physics - The position of a point moving on a circular path is given by the ...
- math - The acceleration am/s^2 of a particle moving in a straight line is given ...
- Math - A car is projected directly up an incline and its location from its start...
- math - a particle M oscillators (that is, moves back and forth) in a straight ...
- Physics - can someone help i'm stuck on two questions??? 23. On a velocity-time ...
- Physics - Maria throws a ball straight up with an initial velocity of 10 m/s. ...
- Calculus - The position of a particle moving on a horizontal line is given by s(...
- physics - A particle moving with uniform acceleration in a straight line was ...

More Related Questions