Homework Help: Physics

Posted by Anonymous on Friday, January 21, 2011 at 2:22pm.

A wood block with a mass of 100 grams is held at the top of an inclined board (point A in Figure 2). If we assume force of friction (Ff) is 0.35N and constant as the block slides down the ramp, what will the velocity be at point B after the block is released and slides down the surface?

Physics - bobpursley, Friday, January 21, 2011 at 3:07pm
ok, the component of gravity down the plane is .1*9.8*cosTheta. That is the force down the plane.

net force=m*a
.98cosTheta-.35=.1*a
solve for acceleration a.
Vf^2=2*a*distance.

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