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ALGEBRA

posted by on .

3+x(12*4)-24
3+x(48)-24
51x-24
51-24=27
48/27
x=1.7?

Not sure if I did the steps correctly.

  • ALGEBRA - ,

    I need to see the original problem first to help you.

    why did you add 48x + 3 to equal 51x?
    then the 'x' is gone in the next line?

  • ALGEBRA - ,

    the original problem is
    3+x(12*4)-24
    and I thought because by 12* 4= 48 then by adding 3 that gave me 51 then I subtracted 24 and that left me with 27 so I divided 48 by 27 and that gave me 1.7 so i placed 1.7 as the x and it's on the other line showing how the steps are broken down. I didn't think it would be correct doing it straight across.

  • ALGEBRA - ,

    3 + x(12*4) - 24

    if that is the problem then,
    3 + 48x - 24
    48x - 21
    48x = 21
    x = 21/48
    x = 7/16

    you can only combine 'like terms'
    x terms can only be added to other x terms, constant terms can only be added to other constant terms.
    do you understand?

  • ALGEBRA - ,

    no I don't because I was going by pemdas.

  • ALGEBRA - ,

    what is 'pemdas'?

  • ALGEBRA - ,

    Parenthesis, Exponents, Multiply, Divide, Add, Subtract (order of operations for evaluating math expressions)

  • ALGEBRA - ,

    I followed that
    3 + x(12*4) = 24

    multiply 12*4
    3 + 48x = 24
    subtract 3 from both sides
    3 - 3 + 48x = 24 - 3
    48x = 21
    divide both sides by 48
    48x/48 = 21/48
    x = 21/48
    reduce fraction
    x = 7/16

  • ALGEBRA - ,

    thank you

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