What is name of reagent containing 0.6 M Sulphuric acid, 28 mM sodium phosphate, and 4 mM ammonium molybdate? and in which amount it should be taken to make a reagent?
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The name of the reagent containing 0.6 M Sulphuric acid, 28 mM sodium phosphate, and 4 mM ammonium molybdate would depend on the specific purpose or use of the reagent. There isn't a specific name for this combination of chemicals alone.
To make this reagent, you will need to calculate the amounts of each chemical required based on their respective molarities and the desired volume of the reagent. Here's how you can do it:
1. Determine the desired volume of the reagent. Let's say you want to make 100 mL of the reagent.
2. Calculate the volume of each component based on their molarities:
a) Sulphuric acid (H2SO4):
- Molarity: 0.6 M
- Moles = Molarity x Volume (in liters)
- Volume (in liters) = Moles / Molarity
- Volume (in mL) = Volume (in liters) x 1000 mL
b) Sodium phosphate (Na3PO4):
- Concentration: 28 mM (millimoles per liter)
- Moles = Concentration x Volume (in liters)
- Volume (in liters) = Moles / Concentration
- Volume (in mL) = Volume (in liters) x 1000 mL
c) Ammonium molybdate ((NH4)2MoO4):
- Concentration: 4 mM (millimoles per liter)
- Moles = Concentration x Volume (in liters)
- Volume (in liters) = Moles / Concentration
- Volume (in mL) = Volume (in liters) x 1000 mL
3. Calculate the volumes of each component based on the desired volume of the reagent. Multiply the calculated volumes from step 2 by the desired reagent volume (100 mL in our example).
4. Combine the calculated volumes of each component in a suitable container to obtain the reagent with the desired composition.
Note: It's important to handle these chemicals safely and ensure proper lab procedures and protocols are followed while making this reagent.