Posted by Anonymous on .
To determine the density of block of aluminum, you measured the mass at 101.1 g and a volume of 38.2 cm3 . When you looked up the value for aluminum density you found out it should be 2700 kg/m3 What is the percent error for your experimental data?
a) 1.98%
c) 19.8%
b) 0.198 %
d) cannot determine

physics 
Henry,
101.1g = 0.1011kg,
V = 10^6m^3/cm^3 * 38.2cm^3 =
38.2*10^6m^3.
Density = 0.1011kg / 38.2*10^6m^3 =
2.6466*10^3 * 10^6 = 2647kg/m^3.
Error = 2700  2647 = 53kg/m^3.
%Error = (53/2700) * 100% = 1.96.
ans. = a.