I have tried to solve this problem several time sto get the answer and I am lost.

Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hr abd train B is traveling at 90 miles per hr. Train A passes a station at 3:25am,if train B passes the same station at 3:37am, at what time will train B catch up train A???

Rather than "Help" as th Scho ol Subject, MATH would get you the right volunteer teacher.

Sra

To solve this problem, we can use the concept of relative speed and time.

Let's first determine the time difference between when Train A passed the station and when Train B passed the same station.

Train A passed the station at 3:25 am, and Train B passed the same station at 3:37 am. The time difference is 12 minutes.

Next, let's calculate the distance covered by Train A during this time difference. Since Train A is traveling at a speed of 80 miles per hour, we can use the formula:

Distance = Speed × Time

Distance covered by Train A = 80 mph × (12/60) hr (converting minutes to hours by dividing by 60)

Distance covered by Train A = 80 mph × 0.2 hr

Distance covered by Train A = 16 miles

Now we know that Train B needs to catch up to Train A, which is 16 miles ahead.

To find the time when Train B catches up to Train A, we can use the formula:

Time = Distance / Speed

Time taken by Train B = 16 miles / 90 mph

Time taken by Train B = 0.1778 hr

Now we need to add this time to the time Train B passed the station (3:37 am) to find the total time:

Total time = 3:37 am + 0.1778 hr

Converting 0.1778 hours to minutes gives us 10.67 minutes.

Therefore, Train B will catch up to Train A approximately 10.67 minutes after 3:37 am.

Adding this to 3:37 am, we can calculate the approximate time when Train B catches up to Train A.