if 3.5 moles of HCl are used how many moles of AlCl(sub3) are produced
with the equation Al(OH)(sub3)+ 3HCl= AlCl(sub3) + 3H(sub2)O
3.5 mol HCl x (1 mol AlCl3/3 mol HCl) = ??
To determine the number of moles of AlCl3 produced from 3.5 moles of HCl, we need to know the balanced chemical equation for the reaction between HCl and AlCl3. Without it, we cannot provide an accurate answer.
However, I can guide you on how to calculate the number of moles of AlCl3 produced once you have the balanced chemical equation. Here's the general process:
1. Write the balanced chemical equation for the reaction between HCl and AlCl3.
For example:
`2 AlCl3 + 6 HCl -> 2 AlCl(sub3) + 3 H2`
2. Identify the mole ratio between HCl and AlCl3 from the balanced equation.
In the given equation, the mole ratio is 6 moles of HCl react with 2 moles of AlCl3.
3. Use the mole ratio to calculate the number of moles of AlCl3 produced.
Multiply the given number of moles of HCl by the mole ratio.
In this case, if you have 3.5 moles of HCl:
`3.5 moles HCl * (2 moles AlCl3 / 6 moles HCl) = 1.17 moles AlCl3`
Therefore, if the balanced chemical equation is 2 AlCl3 + 6 HCl -> 2 AlCl(sub3) + 3 H2, then 3.5 moles of HCl would produce approximately 1.17 moles of AlCl3.