Posted by **APPRECIATIVE STUDENT** on Thursday, January 20, 2011 at 7:38pm.

hi -- thank you for your help before-- that makes sense--

also, im stuck on this: if there is a negative2.5 microcoulomb charge 1 m away from a 6microcoulomb charge, then at what point (other than infinity) is the electric field = zero?

Sorry, i have no idea how to do this, i tried finding F using Kq1q2/ r^2 but im not sure what is next...or if that is even correct..?

- science(physics) -
**bobpursley**, Thursday, January 20, 2011 at 7:47pm
WEll, E is a vector. If the charges are the same, between them the individual E are in opposite directions, so if at the right point, E adds to zero

k*2.5E-6/x^2 -k6E-6/(1-x)^2=0

solve for x.

notice it is a quadratic.

- science(physics) -
**APPRECIATIVE STUDENT**, Thursday, January 20, 2011 at 7:53pm
thank you!

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