Posted by ash on .
Someone attaches a 27 kg bale of hay to one end of a rope passing over a frictionless pulley connected to a beam in a hay barn. Someone else pull down on the opposite en of the rope with a force of 397 N. Ignoring the mass of the rope, what will be the magnitude and directionf the bales acceleration if the gravitational force is 265 N?
Just use F = M*a, where:
M = bale mass = 27 kg,
F = net force = T - Weight
T = pulling force, which will be the tension on either side of the pulley.
Weight = M g = 265 N
a = F/M = (397-265)/27 = 4.9 m/s^2
Ok, that's what I got but I wasn't sure if it was correct. Thanks so much!