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March 30, 2017

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Given a right triangle whose side lengths are integral multiples of 7, how many units are in the smallest possible perimeter

  • algebra - ,

    The smallest possible perimeter is obtained when we have the smallest possible sides.
    But the sides are supposed to be multiples of 7
    So they have to be 7 and 14
    Hypotenuse^2 = 7^2 + 14^2
    Hypotenuse = √245

    so smallest possible perimter = 7+14+√245
    = 21 + √245

  • algebra - ,

    21 + [(square root of 5) x 7]

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