Posted by **algebra** on Thursday, January 20, 2011 at 5:15pm.

Given a right triangle whose side lengths are integral multiples of 7, how many units are in the smallest possible perimeter

- algebra -
**Reiny**, Thursday, January 20, 2011 at 6:03pm
The smallest possible perimeter is obtained when we have the smallest possible sides.

But the sides are supposed to be multiples of 7

So they have to be 7 and 14

Hypotenuse^2 = 7^2 + 14^2

Hypotenuse = √245

so smallest possible perimter = 7+14+√245

= 21 + √245

- algebra -
**Henry**, Friday, January 1, 2016 at 2:35pm
21 + [(square root of 5) x 7]

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