Posted by algebra on Thursday, January 20, 2011 at 5:15pm.
Given a right triangle whose side lengths are integral multiples of 7, how many units are in the smallest possible perimeter

algebra  Reiny, Thursday, January 20, 2011 at 6:03pm
The smallest possible perimeter is obtained when we have the smallest possible sides.
But the sides are supposed to be multiples of 7
So they have to be 7 and 14
Hypotenuse^2 = 7^2 + 14^2
Hypotenuse = √245
so smallest possible perimter = 7+14+√245
= 21 + √245

algebra  Henry, Friday, January 1, 2016 at 2:35pm
21 + [(square root of 5) x 7]
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