Posted by Onuchukwu Victor on .
A uniform rod 8m long weighing 5kg is supported horizontally by 2 vertical parallel strings @ p & Q and @ distances of 2m and 6m from one end.Weights of 1kg,1.5kg and 2kg are attached at distances of 1m, 5m and 7m respectively from the same end.
Find the tension in each vertical sting
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Assuming it is string and not sting, try some of the following:
DELTA STATE POLYTECHNIC OTEFE-OGHARA,DEPARTMENT OF ELECTRICAL/ELECTRONICS ENGINEERING ND1 SPAT. -
moments of Q Is equal to d distance of d weight times d weight plus d next moment dat is,5*2+1.5*3+2*5 = 1*6,
24.5Q and 6P
The tension in Q is 24.5 N AND P is 6N