Posted by stan on Thursday, January 20, 2011 at 2:00pm.
Hey Stan, is that a direct copy/paste? Ie that's all your were given word for word? Hoi.. I think my Physics is rusty.
yeah that is word for word
Hey again Stan, hmm, okay, I'll keep playing with it, I still say we're missing info though... but re-post in the meantime, so other tutors don't think I've answered.
Acceleration is constant. Initial velocity is zero. You know that from the first sentence.
Vertical location is
Y = -2 + (a/2)t^2
Y(t=2) - Y(t=1) = 3 ft.
(a/2) (2^2 - 1^2)) = (3/2)a = 3
a = 2 ft/s^2
Y(t=3) = -2 + (2/2)*3^2 = 7 feet
Related Questions
physics help - The magnitude of the velocity of a particle which starts from ...
physics - A particle starts from the origin with a velocity of 6.0 i m/s and ...
Physics - F=6kt This force acts on a particle of mass "m" that moves ...
Physics - In the figure, particle A moves along the line y = 26 m with a ...
physics - In the figure, particle A moves along the line y = 29 m with a ...
differential equation or physics - A particle moves on the x-axis with an ...
Calculus based physics - A particle travels along a path described by the ...
Physics - A particle starts from xi = 10 m at t0 = 0 and moves with the velocity...
Physics - A particle leaves the origin with a velocity of 7.2 m/s in the ...
physics - A particle moves in the xy plane with constant acceleration. At time ...
For Further Reading
