Posted by Michael on .
The following reaction mechanism has been proposed for a reaction:
(slow) NO2 + NO2-> NO3 + NO
(fast) NO3 + CO -> CO2 + NO2
A. Write the equation for the overall reaction from the mechanism above.
B.Write the rate law for the reaction
A) For the first step you want to take the reactants from both the slow and fast steps and put them on the left of the arrow. And put all four products on the right side. Then cancel out anything that appears on both (Ex: NO2) Then make sure all your elements are balanced and you have your overall equation.
B) Your rate law is r = k[products]^order. Remember that your slow step is your rate determining step.